By Remainder theorem, remainder of $x^{3} - 6x^{2} + 11x - 6$ divided by $(x - 1)$ is

By Remainder theorem, remainder of $x^{3} - 6x^{2} + 11x - 6$ divided by $(x - 1)$ is
  1. $0$
  2. $6$
  3. $-6$
  4. $11$

Solution

$p(1) = 1 - 6 + 11 - 6 = 0$.

Asked in: MH-SSC-9

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