By prime factorisation, $\sqrt[3]{216}$ equals

By prime factorisation, $\sqrt[3]{216}$ equals
  1. $6$
  2. $4$
  3. $5$
  4. $8$

Solution

$216 = 2^{3} \times 3^{3}$, so $\sqrt[3]{216} = 2 \times 3 = 6$.

Asked in: IMO

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