By cross-multiplication, $\dfrac{x}{b_1 c_2 - b_2 c_1}$ equals (for $a_1 x + b_1 y + c_1 = 0$ and $a_2 x +…

By cross-multiplication, $\dfrac{x}{b_1 c_2 - b_2 c_1}$ equals (for $a_1 x + b_1 y + c_1 = 0$ and $a_2 x + b_2 y + c_2 = 0$)
  1. $\dfrac{-1}{a_1 b_2 - a_2 b_1}$
  2. $\dfrac{1}{a_1 b_2 - a_2 b_1}$
  3. $\dfrac{1}{a_1 b_2 + a_2 b_1}$
  4. $\dfrac{1}{c_1 - c_2}$

Solution

Standard cross-multiplication: $\dfrac{x}{b_1 c_2 - b_2 c_1} = \dfrac{y}{c_1 a_2 - c_2 a_1} = \dfrac{-1}{a_1 b_2 - a_2 b_1}$.

Asked in: MH-SSC-9

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