By Componendo-Dividendo: if $\dfrac{x}{4} = \dfrac{3}{5}$, then $\dfrac{x + 4}{x - 4}$ equals

By Componendo-Dividendo: if $\dfrac{x}{4} = \dfrac{3}{5}$, then $\dfrac{x + 4}{x - 4}$ equals
  1. $-4$
  2. $4$
  3. $\dfrac{8}{2}$
  4. $2$

Solution

$\dfrac{x+4}{x-4} = \dfrac{3+5}{3-5} = \dfrac{8}{-2} = -4$.

Asked in: MH-SSC-9

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