Bromine is liberated when an aqueous solution of potassium bromide is treated with
- $\mathrm{Cl}_{2}$
- $\mathrm{I}_{2}$
- Dilute $\mathrm{H}_{2} \mathrm{SO}_{4}$
- $\mathrm{SO}_{2}$
Solution
\mathrm{Cl}_{2}+2 \mathrm{KBr} ightarrow 2 \mathrm{KCl}+\mathrm{Br}_{2}
$$
A more electronegative halogen can displace less electronegative halogen. ,
Asked in: JEE-TOPICTESTS-CHEMISTRY
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