Boxes $B_1, B_2$, and $B_3$, contain balls as given below: $\begin{array}{ccc} \text { Box } & \text { White…

Boxes $B_1, B_2$, and $B_3$, contain balls as given below: $\begin{array}{ccc} \text { Box } & \text { White } & \text { Black } \\ B_1 & 1 & 2 \\ B_2 & 3 & 1 \\ B_3 & 2 & 3 \end{array}$ One ball is drawn at random from each box. Then, among the balls drawn, the probability that two are black and one is white, is
  1. $\frac{5}{12}$
  2. $\frac{7}{12}$
  3. $\frac{9}{12}$
  4. $\frac{11}{12$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

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