Blocks of masses m ,   2 m ,   4 m and 8 m are arranged in a line of a frictionless floor. Another block of mass m , moving with speed υ along the same line (see figure) collides with mass m in perfectly inelastic manner. All the subsequent collisions are also perfectly inelastic.…

Question

Blocks of masses m , &#160; 2 m , &#160; 4 m and 8 m are arranged in a line of a frictionless floor. Another block of mass m , moving with speed &#965; along the same line (see figure) collides with mass m in perfectly inelastic manner. All the subsequent collisions are also perfectly inelastic. By the time the last block of mass 8 m starts moving the total energy loss is p% of the original energy. Value of &lsquo; p &rsquo; is close to:

Aicharya · Accepted Answer

Inelastic collision mv = 16 &#8201; mv 1 &#916;K &#8201; loss = 1 2 mv 2 &#8722; 1 2 16 M v 16 2 = 1 2 mv 2 &#8722; 1 2 M v 2 16 = 1 2 mv 2 15 16 % &#160; &#916;K &#8201; loss = 1 2 mv 2 15 16 1 2 MV 2 &#215; 100 = 15 16 &#215; 100 = 93 .75 %

Blocks of masses m ,   2 m ,   4 m and 8 m are arranged in a line of a frictionless floor. Another…

Solution

Blocks of masses m , &#160; 2 m , &#160; 4 m and 8 m are arranged in a line of a frictionless floor. Another…

Solution

Blocks of masses m , 2 m , 4 m and 8 m are arranged in a line of a frictionless floor. Another…