Binding energy of a certain nucleus is $18 \times 10^8 \mathrm{~J}$. How much is the difference between…

Binding energy of a certain nucleus is $18 \times 10^8 \mathrm{~J}$. How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:
  1. $10 \mu \mathrm{g}$
  2. $20 \mu \mathrm{g}$
  3. $0.2 \mu \mathrm{g}$
  4. $2 \mu \mathrm{g}$

Solution

$\begin{aligned} & \Delta \mathrm{mc}^2=18 \times 10^8 \\ & \Delta \mathrm{m} \times 9 \times 10^{16}=18 \times 10^8 \\ & \Delta \mathrm{m}=2 \times 10^{-8} \mathrm{~kg}=20 \mu \mathrm{g}\end{aligned}$

Asked in: JEE Main 2024 (08 Apr Shift 1)

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