Benzamide $\xrightarrow{\mathrm{Br}_2 / \mathrm{NaOH}} \mathrm{X} \xrightarrow[\text { alc. }…

Benzamide $\xrightarrow{\mathrm{Br}_2 / \mathrm{NaOH}} \mathrm{X} \xrightarrow[\text { alc. } \mathrm{KOH}]{\mathrm{CHCl}_3} \mathrm{Y}$ The conversion of X to Y is
  1. Hoffmann reaction
  2. Etard reaction
  3. Stephen reaction
  4. Carbylamine reaction

Asked in: AP EAMCET 2024 (20 May Shift 1)

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