Based on the cell notation for a spontaneous reaction, at the anode :…

Based on the cell notation for a spontaneous reaction, at the anode :
$\mathrm{Ag}(\mathrm{s})|\mathrm{AgCl}(\mathrm{s})| \mathrm{Cl}^{-}(\mathrm{aq}) \| \mathrm{Br}^{-}(\mathrm{aq})\left|\mathrm{Br}_{2}(l)ight| \mathrm{C}(\mathrm{s})$
  1. AgCl gets reduced
  2. Ag gets oxidized
  3. $\mathrm{Br}^{-}$ gets oxidized
  4. $\mathrm{Br}_{2}$ gets reduced

Solution

Ag becomes oxidized and $\mathrm{Br}^{-}$ becomes reduced.

Asked in: JEE-TOPICTESTS-CHEMISTRY

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