Base strength of (i) \(\mathrm{H}_3 \mathrm{C} \stackrel{\ominus}{\mathrm{C}} \mathrm{H}_2\) (ii)…

Base strength of (i) \(\mathrm{H}_3 \mathrm{C} \stackrel{\ominus}{\mathrm{C}} \mathrm{H}_2\) (ii) \(\mathrm{H}_2 \mathrm{C}=\stackrel{\ominus}{\mathrm{C}} \mathrm{H}\) (iii) \(H-C \equiv C^{\ominus}\) is in the order of
  1. (ii) \(>\) (i) \(>\) (iii)
  2. (iii) \(>\) (ii) \(>\) (i)
  3. (i) \(>\) (iii) \(>\) (ii)
  4. (i) \(>\) (ii) \(>\) (iii)

Solution

Weaker the acid, strongest is its conjugate base. Among alkane, alkene and alkyne, alkynes are most acidic and alkanes are least acidic, so the order of base strength is alkane \(>\) alkene \(>\) alkyne or \(\mathrm{CH}_3 \stackrel{\ominus}{\mathrm{C}} \mathrm{H}_2 > \mathrm{H}_2 \mathrm{C}=\stackrel{\ominus}{\mathrm{C}} \mathrm{H} > \mathrm{H}-\mathrm{C} \equiv \stackrel{\ominus}{\mathrm{C}}\)

Asked in: NEET 2008 (Mains)

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