$3.011 \times 10^{22}$ atoms of an element weighs $1.15 \mathrm{~g}$. The atomic mass of the element is
$3.011 \times 10^{22}$ atoms of an element weighs $1.15 \mathrm{~g}$. The atomic mass of the element is
$23$
$10$
$16$
$35.5$
Solution
From Avogadro's law,
Avogadro's number $=$ Atomic mass of the element
$\because 3.011 \times 10^{22}$ atoms of an element weigh $=1.15 \mathrm{~g}$
$\therefore 6.023 \times 10^{23}$ atoms weigh
$=\frac{1.15 \times 6.023 \times 10^{23}}{3.011 \times 10^{22}}=23$