At very high frequencies, the effective impedance of the given circuit will be _________ Ω .

At very high frequencies, the effective impedance of the given circuit will be _________$\mathrm{\Omega }.$

Solution

For $\omega \to \infty$
$\frac{1}{\omega C}\to 0\Rightarrow$ capacitance acts as short circuit
& $\omega \mathrm{L}\to \infty$ Inductance acts as open circuit

$Z=1+\frac{2\times 2}{2+2}=2\mathrm{\Omega }$

Asked in: JEE Main 2021 (31 Aug Shift 2)

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