At the temperature T ( K ) for the reaction X 2 O 4   l → 2 XO 2   g   ΔU = x…

At the temperature T(K) for the reaction X2O4 l→2XO2 g ΔU=x kJ mol-1 ΔS=y JK-1 mol-1. Gibbs energy change for the reaction is
(Assume X2O4, XO2 are ideal gases)
  1. 1000x+2R(T-y)J mol-1
  2. 1000x+T(2R-y)J mol-1
  3. x+T(2R-y)J mol-1
  4. x+2R(T-y)J mol-1

Solution

∆G = ∆H -T∆S∆H = ∆U +∆ngRT∆G =∆U +∆ngRT-T∆S ∆G =1000x +2RT-Ty∆G =1000x +T(2R-y)..

Asked in: AP EAMCET 2018 (25 Apr Shift 1)

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