At $\mathrm{T}(\mathrm{K})$, the solubility product of AX is $10^{-10}$. What is the molar solubility of AX…
At $\mathrm{T}(\mathrm{K})$, the solubility product of AX is $10^{-10}$. What is the molar solubility of AX in 0.1 M HX solution?
- $10^{-5}$
- $10^{-10}$
- $10^{-9}$
- $10^{-8}$
Solution
Solubility product $\left(\mathrm{K}_{\mathrm{sp}}\right)$ of $\mathrm{AX}=10^{-10}$
$\begin{aligned}
& {\left[\mathrm{H}^{+}\right]=\left[\mathrm{X}^{-}\right]=10^{-1} \mathrm{M}} \\
& {\left[\mathrm{~K}_{\mathrm{sp}}\right]=\left[\mathrm{H}^{+}\right]\left[\mathrm{X}^{-}\right]} \\
& 10^{-10}=\left[10^{-1}\right] \times[\mathrm{S}] \\
& \therefore \quad \mathrm{S}=\frac{10^{-10}}{10^{-1}}=10^{-9}
\end{aligned}$
Asked in: AP EAMCET 2024 (21 May Shift 1)
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