At $\mathrm{T}(\mathrm{K})$, the molar conductivity of $0.04 \mathrm{M}$ acetic acid is $7.8 \mathrm{~S}…

At $\mathrm{T}(\mathrm{K})$, the molar conductivity of $0.04 \mathrm{M}$ acetic acid is $7.8 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$. If the limiting molar conductivities of $\mathrm{H}^{+}$and $\mathrm{CH}_3 \mathrm{COO}^{-}$at $\mathrm{T}(\mathrm{K})$ are 349 and $41 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}$ respectively, the dissociation constant of acetic acid is
  1. $1.63 \times 10^{-5}$
  2. $8.33 \times 10^{-5}$
  3. $1.63 \times 10^{-4}$
  4. $8.33 \times 10^{-4}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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