At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase…

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is:
  1. π2 radian
  2. π radian
  3. π8 radian
  4. π4 radian

Solution

For first minima
AP-BP=λ

AP-MP=λ2
So phase difference =2πλ×λ2=π

Asked in: NEET 2015 (Phase 2)

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