At $300 \mathrm{~K}$, one mole of a gas present in a $10 \mathrm{~L}$ flask exerted a pressure of $2.706…

At $300 \mathrm{~K}$, one mole of a gas present in a $10 \mathrm{~L}$ flask exerted a pressure of $2.706 \mathrm{~atm}$. What is its compressibility factor $(\mathrm{Z})$ ? (Given $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ ).
  1. $1.0$
  2. $1.5$
  3. $0.91$
  4. $1.1$

Solution

$Z=\frac{P V}{R T}=\frac{(2.706)(10)}{(0.082)(300)}=1.1$

Asked in: AP EAMCET 2023 (15 May Shift 2)

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