At $T(\mathrm{~K})$ if the rate constant for a zero order reaction is $2.5 imes 10^{-3} \mathrm{~ms}^{-1}$, the time required for the initial concentration of reactant, $R$ to fall from $0.10 \mathrm{M}$ to $0.075 \mathrm{M}$ at the same temperature in seconds is

Question

At $T(\mathrm{~K})$ if the rate constant for a zero order reaction is $2.5 	imes 10^{-3} \mathrm{~ms}^{-1}$, the time required for the initial concentration of reactant, $R$ to fall from $0.10 \mathrm{M}$ to $0.075 \mathrm{M}$ at the same temperature in seconds is

Aicharya · Accepted Answer

$\begin{aligned} t & =\frac{\left[R_0ight]-[R]_E}{K} \quad t=\frac{0.1-0.075}{2.5 	imes 10^{-3}} \ & =\frac{0.025}{2.5 	imes 10^{-3}} t=0.01 	imes 10^3=10 \mathrm{~s}\end{aligned}$

At $T(\mathrm{~K})$ if the rate constant for a zero order reaction is $2.5 \times 10^{-3} \mathrm{~ms}^{-1}$…

Solution