At constant temperature, the pressure of gas is decreased by $20 \%$. The percentage change in volume
At constant temperature, the pressure of gas is decreased by $20 \%$. The percentage change in volume
increase by $29 \%$
decreases by $25 \%$
increases by $25 \%$
decreases by $20 \%$
Solution
Ideal gas equation states that: $P V=n R T$
As temperature remains constant, so $P V=$ constant
As pressure decreases by $20 \%$, so $P_2=0.8 P$
$\begin{aligned} & \Rightarrow P V=(0.8 P) V_2 \\ & \Rightarrow V_2=\frac{P V}{0.8 P}=\frac{V}{0.8}=1.25 \mathrm{~V}\end{aligned}$
So, volume of gas increase by $25 \%$