At a particular temperature, the vapour pressures of two liquids $\mathrm{A}$ and $\mathrm{B}$ are respectively 120 and $180 \mathrm{~mm}$ of mercury. If 2 moles of $\mathrm{A}$ and 3 moles of $\mathrm{B}$ are mixed to form an ideal solution, the vapour pressure of the solution at the same…

Question

At a particular temperature, the vapour pressures of two liquids $\mathrm{A}$ and $\mathrm{B}$ are respectively 120 and $180 \mathrm{~mm}$ of mercury. If 2 moles of $\mathrm{A}$ and 3 moles of $\mathrm{B}$ are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm of mercury)

Aicharya · Accepted Answer

Vapour pressure of solution $=\mathrm{P}_{\mathrm{A}}+\mathrm{P}_{\mathrm{B}}$
$=\mathrm{P}_{\mathrm{A}}^{\mathrm{o}} \mathrm{X}_{\mathrm{A}}+\mathrm{P}_{\mathrm{B}}^{\mathrm{O}} \mathrm{X}_{\mathrm{B}}=\frac{120 \times 2}{5}+\frac{180 \times 3}{5}$
$=156 \mathrm{~mm} \mathrm{Hg}$

At a particular temperature, the vapour pressures of two liquids $\mathrm{A}$ and $\mathrm{B}$ are…

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