At a particular angular frequency, the reactance of capacitor and that of inductor is same. If the angular frequency is doubled, the ratio of the reactance of the capacitor to that of the inductor will be

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Aicharya · Accepted Answer

We know, $X_L=\omega L$ ....(i) $\Rightarrow X_L \propto \omega$ Similarly, $\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega c}$ Given $X_L^1=2 X_L$ $\ldots .(\because \omega=2 \omega)$ $X_C^1=\frac{X_c}{2}$ $	herefore \quad \frac{\mathrm{X}_{\mathrm{C}}^1}{\mathrm{X}_{\mathrm{L}}^1}=\frac{\frac{\mathrm{X}_{\mathrm{C}}}{2}}{2 \mathrm{X}_{\mathrm{L}}}=\frac{1}{4}$ ...(from (i))

At a particular angular frequency, the reactance of capacitor and that of inductor is same. If the angular…

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