At a given temperature, the density of an ideal gas is proportional to ($\mathrm{P}=$ pressure of ideal gas)

At a given temperature, the density of an ideal gas is proportional to ($\mathrm{P}=$ pressure of ideal gas)
  1. $\frac{1}{\mathrm{P}}$
  2. $\mathrm{P}$
  3. $\mathrm{P}^2$
  4. $\sqrt{\mathrm{P}}$.

Solution

$\mathrm{d}=\frac{\mathrm{m}}{\mathrm{V}}=\frac{(\mathrm{n} \times \mathrm{M})}{\frac{\mathrm{nRT}}{\mathrm{P}}}=\frac{\mathrm{PM}}{\mathrm{RT}}=\left(\frac{\mathrm{M}}{\mathrm{RT}}\right) \mathrm{P}$ Thus, $\mathrm{d} \alpha \mathrm{P}$

Asked in: AP EAMCET 2023 (16 May Shift 1)

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