At $\mathrm{T}(\mathrm{K})$, a gaseous mixture containing $\mathrm{H}_2, \mathrm{He}$ and $\mathrm{O}_2$ exerted a pressure of 1 bar. The weight percentage of $\mathrm{H}_2$ and $\mathrm{He}$ is 20 and 16 respectively. The partial pressure (in bar) of $\mathrm{H}_2, \mathrm{He}$ and $\mathrm{O}_2$…

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At $\mathrm{T}(\mathrm{K})$, a gaseous mixture containing $\mathrm{H}_2, \mathrm{He}$ and $\mathrm{O}_2$ exerted a pressure of 1 bar. The weight percentage of $\mathrm{H}_2$ and $\mathrm{He}$ is 20 and 16 respectively. The partial pressure (in bar) of $\mathrm{H}_2, \mathrm{He}$ and $\mathrm{O}_2$ is respectively

Aicharya · Accepted Answer

$P_{	ext {total }}=1 \mathrm{bar}$, Let total mass $=100 \mathrm{~g}$ $\begin{aligned} & \Rightarrow \mathrm{W}\left(\mathrm{H}_2ight)=20 \mathrm{~g}, \mathrm{~W}(\mathrm{He})=16 \mathrm{~g}, \mathrm{~W}\left(\mathrm{O}_2ight)=64 \mathrm{~g} \ & \Rightarrow \mathrm{n}\left(\mathrm{H}_2ight)=\frac{20}{2}=10 \mathrm{~mol} \ & \mathrm{n}(\mathrm{He})=\frac{16}{4}=4 \mathrm{~mol} \ & \mathrm{n}\left(\mathrm{O}_2ight)=\frac{64}{32}=2 \mathrm{~mol} \ & \Rightarrow \mathrm{x}\left(\mathrm{H}_2ight)=\frac{10}{10+4+2}=\frac{10}{16}=0.625 \ & \mathrm{x}(\mathrm{He})=\frac{4}{16}=0.250\end{aligned}$ $\begin{aligned} & x\left(\mathrm{O}_2ight)=\frac{2}{16}=0.125 \ & \Rightarrow P\left(\mathrm{H}_2ight)=\mathrm{x}_{\mathrm{H}_2} \mathrm{P}_{	ext {total }}=0.625 	imes 1=0.625 \ & \mathrm{P}(\mathrm{He})=0.25 	ext { and } \mathrm{P}\left(\mathrm{O}_2ight)=0.125\end{aligned}$

At $\mathrm{T}(\mathrm{K})$, a gaseous mixture containing $\mathrm{H}_2, \mathrm{He}$ and $\mathrm{O}_2$…

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