At 143   K , the reaction of X e F 4 with O 2 F 2 produces a xenon compound Y . The total number of lone pair(s) of electrons present on the whole molecule of Y is __________

Question

At 143 &#160; K , the reaction of X e F 4 with O 2 F 2 produces a xenon compound Y . The total number of lone pair(s) of electrons present on the whole molecule of Y is __________

Aicharya · Accepted Answer

XeF 4 + O 2 F 2 → XeF 6 + O 2 So Y is XeF 6 Each F atom contains three lone pairs and Xe atom contain one lone pair. so total lone pair = 3 × 6 + 1 = 19 Total L . P = 19 .

At 143   K , the reaction of X e F 4 with O 2 F 2 produces a xenon compound Y . The total number of…

Solution

At 143 &#160; K , the reaction of X e F 4 with O 2 F 2 produces a xenon compound Y . The total number of…

Solution

At 143 K , the reaction of X e F 4 with O 2 F 2 produces a xenon compound Y . The total number of…