Assuming the balls to be identical except for difference in colours, the number of ways in which one or more…
Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from $10$ white, $9$ green and $7$ black balls is
$880$
$629$
$630$
$879$
Solution
Number of ways of selecting one or more balls from $10$ white, $9$ green, and $7$ black balls $=(10+1)(9+1)(7+1)-1=11 \times 10 \times 8-1=879.$