Assuming that junction diode is ideal, the current in arrangement shown in figure
Assuming that junction diode is ideal, the current in arrangement shown in figure
2 mA
20 mA
30 mA
10 mA
Solution
For the given circuit, as the diode is forward biased, current will flow through it.
$\mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{3-1}{100}=\frac{2}{100}=\frac{20}{1000}=20 \mathrm{~mA}$
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