Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule…
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule $\mathrm{B}_2$ is
- 1 and diamagnetic
- 0 and diamagnetic
- 1 and paramagnetic
- 0 and paramagnetic
Solution
$\mathrm{B}_2$ : Total electrons $=10$
Configuration : $\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \pi 2 p_x^1=\pi 2 p_y^1$
If Hunds rule is violated, then
$
\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \quad \pi 2 p_x^2=\pi 2 p_y^0
$
So, diamagnetic
$
\text { Bond order }=\frac{6-4}{2}=1
$
Chemical bonding
Conceptual
II
Asked in: JEE Advanced 2010 (Paper 2)
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