Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule…

Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule $\mathrm{B}_2$ is
  1. 1 and diamagnetic
  2. 0 and diamagnetic
  3. 1 and paramagnetic
  4. 0 and paramagnetic

Solution

$\mathrm{B}_2$ : Total electrons $=10$ Configuration : $\sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \pi 2 p_x^1=\pi 2 p_y^1$ If Hunds rule is violated, then $ \sigma 1 s^2 \sigma^* 1 s^2 \sigma 2 s^2 \sigma^* 2 s^2 \quad \pi 2 p_x^2=\pi 2 p_y^0 $ So, diamagnetic $ \text { Bond order }=\frac{6-4}{2}=1 $ Chemical bonding Conceptual II

Asked in: JEE Advanced 2010 (Paper 2)

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