Assuming complete ionisation, arrange the following solutions in order of increasing osmotic pressure. a) $0…
Assuming complete ionisation, arrange the following solutions in order of increasing osmotic pressure.
a) $0.5 \mathrm{~m} \mathrm{Li}_2 \mathrm{SO}_4$.
b) $\quad 0.5 \mathrm{mKCl}$
c) $\quad 0.5 \mathrm{~m} \mathrm{Al}_2\left(\mathrm{SO}_4\right)_3$
d) $0.1 \mathrm{~m} \mathrm{BaCl}_2$
d $ \lt $ b $ \lt $ a $ \lt $ c
b $ \lt $ d $ \lt $ c $ \lt $ a
a $ \lt $ d $ \lt $ c $ \lt $ b
c $ \lt $ d $ \lt $ b $ \lt $ a
Solution
Osmotic pressure is a colligative property that depends on number of particles in solution. The solution having more number of particles will have larger osmotic pressure.
Hence, $\mathrm{Al}_2\left(\mathrm{SO}_4\right)_3$ solution gives more number of particles and has the highest osmotic pressure among the given. So, the correct order of increasing osmotic pressure is $\mathrm{d} \lt \mathrm{b} \lt \mathrm{a} \lt \mathrm{c}$
