Assume that a neutron breaks into a proton and an electron. The energy released during this process is (Mass…

Assume that a neutron breaks into a proton and an electron. The energy released during this process is (Mass of neutron $=1.6725 \times 10^{-27} \mathrm{~kg} ;$ mass of proton $=1.6725 \times 10^{-27} \mathrm{~kg} ;$ mass of electron $=9 \times 10^{-31}$ $\mathrm{kg})$
  1. $0.73 \mathrm{~MeV}$
  2. $7.10 \mathrm{~MeV}$
  3. $6.30 \mathrm{~MeV}$
  4. $5.4 \mathrm{~MeV}$

Solution

$\begin{aligned} \Delta m & =\left(m_p+m_e\right)-m_n \\ & =9 \times 10^{-31} \mathrm{~kg}. \end{aligned}$ Energy released $=\left(9 \times 10^{-31} \mathrm{~kg}\right) \mathrm{c}^2$ joules $\begin{aligned} & =\frac{9 \times 10^{-31} \times\left(3 \times 10^8\right)^2}{1.6 \times 10^{-13}} \mathrm{MeV} \\ & =0.73 \mathrm{~MeV} . \end{aligned}$

Asked in: JEE Main 2012 (Offline)

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