Assume a cell with the following reaction Cu ( s ) + 2 Ag + 1 × 10 - 3 M → Cu 2 + ( 0 . 250 M ) +…

Assume a cell with the following reaction Cu(s)+2Ag+1×10-3MCu2+(0.250M)+2Ag(s)
Ecell =2.97 V

Ecell  for the above reaction is         V.

(Nearest integer)

[ Given : log2.5=0.3979, T=298 K]

Solution

E=E°-0.0592logCu+2Ag+2
=2.97-0.0592log0.2510-32=2.81 V

Asked in: JEE Main 2021 (22 Jul Shift 1)

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