Assertion: Equivalent weight of $\mathrm{NH}_3$ in the reaction, $\mathrm{N}_2 \rightarrow \mathrm{NH}_3$ is…
Assertion: Equivalent weight of $\mathrm{NH}_3$ in the reaction, $\mathrm{N}_2 \rightarrow \mathrm{NH}_3$ is $17 / 3$ while that of $\mathrm{N}_2$ is 28/6.
Reason : Equivalent weight
$=\frac{\text { Molecular weight }}{\begin{array}{c}\text { Number of } e^{-} \text {lost or gained } \\ \text { per mole }\end{array}}$
If both assertion and reason are true and reason is the correct explanation of assertion.
If both assertion and reason are true but reason is not the correct explanation of assertion.
If assertion is true but reason is false.
If both assertion and reason are false.
Solution
$: \stackrel{0}{\mathrm{~N}}_2+6 e^{-} \rightarrow 2 \mathrm{~N}^{3-}$
$\therefore \quad$ Equivalent weight of $\mathrm{NH}_3=\frac{14+3}{3}=\frac{17}{3}$
(Mol. wt. of $\mathrm{NH}_3=17$ )
While, equivalent weight of $\mathrm{N}_2=\frac{14 \times 2}{6}=\frac{28}{6}$