Assertion (A): When plane of coil is perpendicular to magnetic field, magnetic flux linked with the coil is minimum, but induced $e m f$ is zero
Reason $(R) : ϕ = n A B \cos θ$ and $e = \frac{d ϕ}{d t}$

Question

Assertion (A): When plane of coil is perpendicular to magnetic field, magnetic flux linked with the coil is minimum, but induced

e m f

is zero
Reason

(R) : ϕ = n A B \cos θ

and

e = \frac{d ϕ}{d t}

Aicharya · Accepted Answer

According to faraday's law of induction, induced $emf e = - \frac{d ϕ}{d t}$

$ϕ$ is the magnetic flux linkage with the coil it is defined as, $ϕ = \vec{B} \cdot \vec{∆ s}$ or $ϕ = B ∆ s \cos θ,$ here, $θ$ is the angle between the magnetic field vector and area vector, therefore, when $θ = 0 °, ϕ$ has maximum value and for $θ = 90 °, ϕ$ has minimum value.

Thus, when plane of coil is perpendicular to magnetic field, magnetic flux linked with the coil is minimum, therefore induced emf is zero.

Assertion (A): When plane of coil is perpendicular to magnetic field, magnetic flux linked with the coil is…

Solution