Assertion (A) The range of a projectile is maximum when the angle of projection is \(45^{\circ}\). Reason…

Assertion (A) The range of a projectile is maximum when the angle of projection is \(45^{\circ}\). Reason (R) The range of a projectile depends only on the angle of projection.
  1. Both (A) and (R) are true and (R) is the correct explanation of \((A)\).
  2. Both (A) and (R) are true but \((R)\) is not the correct explanation of \((A)\).
  3. (A) is true but (R) is false.
  4. (A) is false but \((R)\) is true.

Solution

Assertion is true. (A) The range of projectile is maximum when the angle of projection is \(45^{\circ}\). \(R_{\max }=\frac{u^2 \sin (2 \times 45)}{g}=\frac{u^2}{g}\) But reason \((R)\) is false. \(\therefore\) Range of a projectile, \(R=\frac{u^2 \sin 2 \theta}{g}\) Hence, the range of projectile depends on the angle of projection \(\theta\) and initial velocity \(u\). \(\therefore\) (A) \(\rightarrow\) True (B) \(\rightarrow\) False

Asked in: AP EAMCET 2019 (22 Apr Shift 1)

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