Assertion (A) \(S_N 1\) hydrolysis of optically active 2- bromooctane results in the formation of \((\pm)\)…
Assertion (A) \(S_N 1\) hydrolysis of optically active 2- bromooctane results in the formation of \((\pm)\) - octan -2-ol.
Reason (\(\mathrm{R}\)) The reation proceeds through a planar carbocation which can be attacked by the nucleophile from either side.
The correct answer is
(A) and (R) are correct, (R) is the correct explanation of \((\mathrm{A})\)
(A) and \((\mathrm{R})\) are correct but \((\mathrm{R})\) is not the correct explanation of \((\mathrm{A})\)
(A) is correct but \((R)\) is not correct
\((A)\) is not correct but \((R)\) is correct
Solution
Given, Assertion, (A) and the Reason (R), both are correct and the given Reason (R) is the correct explanation of the given (A). Because \(S_{\mathrm{N}} 1\) reactions occurs through the formation of carbocation. And in \(S_{\mathrm{N}} 1\) reaction both front as well rear attack of nucleophile at carbocation are possible. In 2-bromooctane, following carbocation is formed.
Thus, option (a) is the correct answer.
