Assertion (A) : $\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water. Reason (R) :…
Assertion (A) : $\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water.
Reason (R) : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is
Both (A) and (R) are true and (R) is the correct explanation of (A)
Both $(\mathrm{A})$ and $(\mathrm{R})$ are true but $(\mathrm{R})$ is not the correct explanation of (A)
(A) is true, but (R) is not true
(A) is not true, but (R) is true
Solution
$\mathrm{NaCl}$ is less soluble in heavy water than in ordinary water because dielectric constant of ordinary water $(i e, 81)$ is more than that of heavy water (ie, 80).