Assertion (A) At $300 \mathrm{~K}$, kinetic energy of $16 \mathrm{~g}$ of methane is equal to the kinetic…
Assertion (A) At $300 \mathrm{~K}$, kinetic energy of $16 \mathrm{~g}$ of methane is equal to the kinetic energy of 32 $g$ of oxygen.Reason (R) At constant temperature, kinetic energy of one mole of all gases is equal.
Both $(A)$ and $(R)$ are true and $(R)$ is the correct explanation of $(A)$
Both $(A)$ and $(R)$ are true but $(R)$ is not the
correct explanation of $(A)$
$(A)$ is true but $(R)$ is not true
$(A)$ is not true but $(R)$ is true
Solution
Kinetic energy for one mole gas is given by equation,
$
\begin{aligned}
& E=\frac{3}{2} k T \text { (where, } k=\text { Boltzman's constant) } \\
& \therefore \quad E \propto T
\end{aligned}
$
Thus at constant temperature kinetic energy of one mole of any gas is equal