As shown in figure, a 70   kg garden roller is pushed with a force of F → = 200   N at an…

As shown in figure, a 70 kg garden roller is pushed with a force of F→=200 N at an angle of 30° with horizontal. The normal reaction on the roller is (Given g=10 m s-2)

  1. 8002 N
  2. 600 N
  3. 800 N
  4. 2003 N

Solution

Component of the force perpendicular to the ground,

Fsin30°.

Now for equilibrium along vertical direction, we get

N=mg+Fsin30°=70×10+200×12=800 N

Asked in: JEE Main 2023 (31 Jan Shift 1)

Practice more Laws of Motion questions on Aicharya