As a result of change in the magnetic flux linked to the closed loop as shown in the figure, an e.m.f. $V$…

As a result of change in the magnetic flux linked to the closed loop as shown in the figure, an e.m.f. $V$ volt is induced in the loop. The work done (joules) in taking a charge $Q$ coulomb once along the loop is:
  1. $Q V$
  2. $2 Q V$
  3. $\frac{Q V}{2}$
  4. zero

Solution

Work done due to a charge $W=Q V$

Asked in: NEET 2005

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