Array of light is incident at an angle of incidence ' $i$ ' on one surface of a prism of small angle…

Array of light is incident at an angle of incidence ' $i$ ' on one surface of a prism of small angle $\mathrm{A}$ and emerges normally from the other surface. If the refractive index of the material of the prism is ' $\mu$ ', then the angle of incidence is equal to
  1. $\frac{\mathrm{A}}{2 \mu}$
  2. $\frac{\mathrm{A} \mu}{2}$
  3. $\mathrm{A} \mu$
  4. $\frac{\mathrm{A}}{\mu}$

Solution

Given: $\mathrm{e}=0$ $\therefore \quad r_2=0, A=r_1$ Since ' $\mathrm{i}$ ' is small, Snell's law of refraction can be modified to, $\begin{aligned} & \mu=\frac{i}{r_1} \\ \therefore \quad & i=\mu r_1=\mu A \end{aligned}$

Asked in: MHT CET 2023 (13 May Shift 1)

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