Arrangement of following compounds based on their boiling points in the increasing order. $n$-butane,…

Arrangement of following compounds based on their boiling points in the increasing order. $n$-butane, 1-butanol, ethoxyethane and 1-propanol will be
  1. 1-propanol $>n$-butane $>$ ethoxyethane $>$ 1-butanol
  2. $n$-butane $ < $ ethoxyethane $ < 1$-propanol $ < 1$-butanol
  3. $n$-butane $ < 1$-propanol $ < $ ethoxyethane $ < 1$-butanol
  4. 1-propanol $ < n$-butane $ < $ ethoxyethane $ < 1$-butanol

Solution

Boiling point increases with increase in molecular mass so, 1-butanol has higher boiling point than -propanol. Unlike alcohols, ethers do not form hydrogen bonds thus, they have lower boiling points than the corresponding alcohols. Due to weak dipole-dipole interactions, the boiling points of lower ethers are only slightly higher than those of the $n$-alkanes having comparable molecular masses. Thus, the increasing order of boiling points is $n$-butane $ < $ ethoxyethane $ < 1$-propanol $ < 1$-butanol.

Asked in: MHT CET Full Test 11

Practice more Alcohols Phenols and Ethers questions on Aicharya