Arrange the oxides $\mathrm{CrO}, \mathrm{CrO}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3$ in the decreasing order…

Arrange the oxides $\mathrm{CrO}, \mathrm{CrO}_3$ and $\mathrm{Cr}_2 \mathrm{O}_3$ in the decreasing order of acidic strength
  1. $\mathrm{CrO}_3>\mathrm{Cr}_2 \mathrm{O}_3>\mathrm{CrO}$
  2. $\mathrm{CrO}_3>\mathrm{CrO}>\mathrm{Cr}_2 \mathrm{O}_3$
  3. $\mathrm{CrO}>\mathrm{Cr}_2 \mathrm{O}_3>\mathrm{CrO}_3$
  4. $\mathrm{CrO}>\mathrm{CrO}_3>\mathrm{Cr}_2 \mathrm{O}_3$

Solution

$\mathrm{Cr}$ in higher oxidation state will be more acidic. Thus, the order of acidic strength will be :- $\stackrel{+6}{\mathrm{CrO}_3}>\stackrel{+3}{\mathrm{CrO}} \mathrm{O}_3>\stackrel{+2}{\mathrm{Cr} O}$

Asked in: AP EAMCET 2023 (17 May Shift 2)

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