Arrange the following molecules according to decreasing order of their $\mathrm{O}-\mathrm{O}$ bond lengths.

Arrange the following molecules according to decreasing order of their $\mathrm{O}-\mathrm{O}$ bond lengths.
  1. $\mathrm{O}_3>\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_2$
  2. $\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_3>\mathrm{O}_2$
  3. $\mathrm{O}_2>\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_3$
  4. $\mathrm{O}_2>\mathrm{O}_3>\mathrm{H}_2 \mathrm{O}_2$

Solution

$\mathrm{H}_2 \mathrm{O}_2$ has only single bond with bond length $1.41 Å$, $\mathrm{O}_2$ has double bond with bond length $1.33 Å$. $\mathrm{O}_3$ has a partial double bond due to resonance of lone pairs of electrons.
So, correct order is $\mathrm{H}_2 \mathrm{O}_2>\mathrm{O}_3>\mathrm{O}_2$

Asked in: AP EAMCET 2021 (23 Aug Shift 2)

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