Arrange the following in the increasing order of number of unpaired electrons present in the central metal…
- IV $ \lt $ I $ \lt $ III $ \lt $ II
- $\mathrm{I} \lt \mathrm{III} \lt \mathrm{II} \lt \mathrm{IV}$
- IV $ \lt $ III $ \lt $ I $ \lt $ II
- I $ \lt $ II $ \lt $ III $ \lt $ IV
Solution

So order will be IV $ \lt $ III $ \lt $ I $ \lt $ II.
Asked in: AP EAMCET 2024 (20 May Shift 2)
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