Arrange the following in the correct order of their bond orders.

Question

Aicharya · Accepted Answer

Bond order is the number of chemical bonds present between two atoms of a molecule.

I. $\mathrm{N}_2=\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \pi 2 p_x^2=\pi 2 p_y^2, \sigma 2 p_z^2$ Bond order $=\frac{10-4}{2}=3$ II. $\mathrm{O}_2=\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2$ $\approx 2 p_y^2, \pi^* 2 p_x^1 \approx \pi^* 2 p_y^1$ Bond order $=\frac{10-6}{2}=2$ III. $\mathrm{O}_2^{+}=\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2 \pi 2 p_y^2$,$\pi^* 2 p_x^1$ Bond order $=\frac{10-5}{2}=2.5$ IV. $\mathrm{O}_2^{-}=\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2 \pi 2 p_y^2$,$\pi^* 2 p_x^2 \approx \pi^* 2 p_y^1$ Bond order $=\frac{10-7}{2}=1.5$ Hence, bond order can be arranged as I $>$ III $>$ II $>$ IV

Arrange the following in the correct order of their bond orders.

Solution