Arrange the following in increasing order of solubility product : $\mathrm{Ca}(\mathrm{OH})_2, \mathrm{AgBr}…

Arrange the following in increasing order of solubility product :
$\mathrm{Ca}(\mathrm{OH})_2, \mathrm{AgBr}, \mathrm{PbS}, \mathrm{HgS}$
  1. $\mathrm{HgS} \lt \mathrm{AgBr} \lt \mathrm{PbS} \lt \mathrm{Ca}(\mathrm{OH})_2$
  2. $\mathrm{Ca}(\mathrm{OH})_2 \lt \mathrm{AgBr} \lt \mathrm{HgS} \lt \mathrm{PbS}$
  3. $\mathrm{PbS} \lt \mathrm{HgS} \lt \mathrm{Ca}(\mathrm{OH})_2 \lt \mathrm{AgBr}$
  4. $\mathrm{HgS} \lt \mathrm{PbS} \lt \mathrm{AgBr} \lt \mathrm{Ca}(\mathrm{OH})_2$

Solution

Based on the Ksp values and salt analysis cation identification, we can say that order of Ksp value is:
$\mathrm{HgS} < \mathrm{PbS} < \mathrm{AgBr} < \mathrm{Ca}(\mathrm{OH})_2$
K sp values
$\begin{aligned}
& \mathrm{HgS} \rightarrow 4 \times 10^{-53} \\
& \mathrm{PbS} \rightarrow 8 \times 10^{-28} \\
& \mathrm{AgBr} \rightarrow 5 \times 10^{-13} \\
& \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 5.5 \times 10^{-6}
\end{aligned}$

Asked in: JEE Main 2025 (28 Jan Shift 2)

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