Arrange the following compounds in order of decreasing acidity:

Arrange the following compounds in order of decreasing acidity:
  1. \(\mathrm{II}>\mathrm{IV}>\mathrm{I}>\mathrm{III}\)
  2. \(\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}\)
  3. \(\mathrm{III}>\mathrm{I}>\mathrm{II}>\mathrm{IV}\)
  4. \(\mathrm{IV}>\mathrm{III}>\mathrm{I}>\mathrm{II}\)

Solution

Electron-releasing group decreases the acidity while electron-attracting group increases the acidity. Thus, the molecule III will have maximum acidity and the molecule IV will have minimum acidity. Thus, the choice (c) is correct. .

Asked in: JEE-TOPICTESTS-CHEMISTRY

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