Arrange the following compounds in increasing order of their dipole moment : $\mathrm{HBr}, \mathrm{H}_2 \mathrm{~S}, \mathrm{NF}_3$ and $\mathrm{CHCl}_3$

Question

Aicharya · Accepted Answer

$\begin{aligned}
& \mu_{\mathrm{HBr}}=0.78 \mathrm{D} \\
& \mu_{\mathrm{H}_2 \mathrm{~S}}=0.95 \mathrm{D} \\
& \mu_{\mathrm{NF}_3}=0.24 \mathrm{D} \\
& \mu_{\mathrm{CHCl}_3}=1.01 \mathrm{D}
\end{aligned}$
Hence dipole moment of
$\mathrm{NF}_3 < \mathrm{HBr} < \mathrm{H}_2 \mathrm{~S} < \mathrm{CHCl}_3$

Arrange the following compounds in increasing order of their dipole moment : $\mathrm{HBr}, \mathrm{H}_2…

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