Area of trapezium with parallel sides $a$, $b$ and height $h$ is
Area of trapezium with parallel sides $a$, $b$ and height $h$ is
- $\dfrac{1}{2}(a+b)h$
- $\dfrac{1}{2}ab$
- $abh$
- $2(a+b)h$
Solution
Asked in: MH-SSC-9
Practice more Quadrilaterals questions on Aicharya