Area of trapezium with parallel sides $10$ cm and $14$ cm, height $6$ cm is
Area of trapezium with parallel sides $10$ cm and $14$ cm, height $6$ cm is
- $72$ cm$^{2}$
- $84$ cm$^{2}$
- $48$ cm$^{2}$
- $60$ cm$^{2}$
Solution
$\dfrac{1}{2}(10+14)(6) = 72$.
Asked in: MH-SSC-9
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